How does nozzle flow change with pressure?

Nozzle flow scales with the square root of pressure: Q = Qr·√(P/Pr). Doubling the pressure raises flow by about 41%, so a small pressure change moves the application rate noticeably.

What is the broadcast application rate formula?

GPA = 5940 · Q / (S · W), where Q is gpm per nozzle, S is travel speed in mph and W is nozzle spacing in inches. The 5940 constant folds the acre, mile and minute unit conversions.

How high should a spray boom run?

Set boom height for a 30% double overlap: H = S·(1−0.30) / (2·tan(θ/2)), where S is nozzle spacing and θ is the full fan angle. Too low and the pattern streaks; too high and drift and overlap increase.

What is the flow rate of a TJ60 tip at 40 PSI?

The TJ60 is rated 0.40 gpm at 40 PSI. At 40 PSI the square-root pressure law gives 0.400 gpm.

What GPA does the TJ60 apply?

On a 20 in boom at 5 mph the TJ60 applies 23.8 GPA. GPA = 5940·Q / (S·W), so a faster pass or wider spacing lowers the rate.

How high should the boom run for the TJ60?

Set the boom to 4.9 in for a 30% double overlap with the TJ60's 110° fan. Too low streaks the pattern; too high increases drift and overlap.

TeeJet TJ60 GPA at 40 PSI

Broadcast GPA, nozzle output and tank coverage for a TeeJet TJ60 (Red) tip at 40 PSI.

TeeJet TJ60 at 40 PSI

A TJ60 flat-fan tip (Red, ISO 4) rated at 0.40 gpm and 40 PSI delivers 0.400 gpm at 40 PSI. On a 20 in boom at 5 mph that is 23.8 GPA, covering 8.4 acres per 200 gallon tank, with a 4.9 in boom height for 30% double overlap.

Nozzle output and broadcast GPA

Nozzle output and broadcast GPA is computed deterministically from the parameters encoded in this page's address, so the same inputs always produce the same result and the same OAS-XXXX verification hash.

Tank coverage and boom height

Tank coverage and boom height is computed deterministically from the parameters encoded in this page's address, so the same inputs always produce the same result and the same OAS-XXXX verification hash.

Worked example

Run the TJ60 tip at 40 PSI on a 20 in boom at 5 mph with a 200 gallon tank.

Worked example steps for this calculation
Step	Formula	Value
Nozzle output	Q = Qr·√(P/Pr)	0.400 gpm
Broadcast rate	GPA = 5940·Q / (S·W)	23.8 GPA
Tank coverage	A = tank / GPA	8.4 acres
Boom height	H = S·(1−0.30) / (2·tan(θ/2))	4.9 in

The TJ60 tip puts out 0.400 gpm at 40 PSI, applying 23.8 GPA and covering 8.4 acres per tank at a 4.9 in boom height.

Export this calculation

OAS-4428

Copy the engineering spec, export it as CSV, or print a shop ticket. Every export carries this route's parameter outputs, a timestamp and its OAS-4428 verification hash.

Engineering summary

Governing parameters and computed results for TeeJet TJ60 GPA at 40 PSI.

Governing parameters and computed results for this calculation
Parameter	Value
Nozzle	TJ60
Pressure	40
Nozzle Output (Q)	0.400 gpm
Application Rate (GPA)	23.76 gpa
Acres per Tank	8.42 ac
Boom Height (H)	4.9 in

Frequently asked questions

What is the flow rate of a TJ60 tip at 40 PSI?: The TJ60 is rated 0.40 gpm at 40 PSI. At 40 PSI the square-root pressure law gives 0.400 gpm.
What GPA does the TJ60 apply?: On a 20 in boom at 5 mph the TJ60 applies 23.8 GPA. GPA = 5940·Q / (S·W), so a faster pass or wider spacing lowers the rate.
How high should the boom run for the TJ60?: Set the boom to 4.9 in for a 30% double overlap with the TJ60's 110° fan. Too low streaks the pattern; too high increases drift and overlap.

Spray Nozzle & Boom Calibrator

Pressure-scaled nozzle output, broadcast application rate, tank coverage and optimal boom height for ISO 10605 and TeeJet spray tips.

Result

The TJ60 tip delivers 0.400 gpm at 40.0 psi, applying 23.76 gpa and covering 8.42 acres per 200 gal tank.

23.76gpa

Spray Program

Presets

Parameters

Spray Nozzle

Operating Pressure (P)

psi

Nozzle Spacing (S)

Travel Speed (W)

mph

Tank Size (V)

gal